What is the loading rate of a system with Q= 550GPD and BOD= 350 mg/L?

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Multiple Choice

What is the loading rate of a system with Q= 550GPD and BOD= 350 mg/L?

Explanation:
To determine the loading rate of the system, specifically the biochemical oxygen demand (BOD) load in pounds per day, we need to use the formula: Loading Rate (lbs/day) = (Flow Rate (GPD) x BOD (mg/L)) / 8.34 In this formula: - The flow rate is given as 550 gallons per day (GPD). - The BOD concentration is 350 mg/L. - The factor 8.34 is a conversion factor that translates the units from gallons and mg/L to pounds per day. Using the given values, the calculation would be: Loading Rate = (550 GPD x 350 mg/L) / 8.34 = (192500) / 8.34 ≈ 23,086 lbs/day However, to arrive at a more practical value, let’s focus on converting the loading directly to pounds: First, we calculate the numerator: 550 x 350 = 192500 Next, we divide by 8.34: 192500 / 8.34 = 23050.24 To find the final loading rate in tons (which should align with common usage in wastewater treatment), we would typically use higher conversion factors or

To determine the loading rate of the system, specifically the biochemical oxygen demand (BOD) load in pounds per day, we need to use the formula:

Loading Rate (lbs/day) = (Flow Rate (GPD) x BOD (mg/L)) / 8.34

In this formula:

  • The flow rate is given as 550 gallons per day (GPD).

  • The BOD concentration is 350 mg/L.

  • The factor 8.34 is a conversion factor that translates the units from gallons and mg/L to pounds per day.

Using the given values, the calculation would be:

Loading Rate = (550 GPD x 350 mg/L) / 8.34

= (192500) / 8.34

≈ 23,086 lbs/day

However, to arrive at a more practical value, let’s focus on converting the loading directly to pounds:

First, we calculate the numerator:

550 x 350 = 192500

Next, we divide by 8.34:

192500 / 8.34 = 23050.24

To find the final loading rate in tons (which should align with common usage in wastewater treatment), we would typically use higher conversion factors or

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